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Ohm's-law loop-budget model, consistent with NFPA 72 IDC design practice8 min read

Worked Example: Standby and Alarm Voltage at the Farthest Device on a 10-Detector Loop

A ten-detector initiating device circuit, checked in both its quiet standby state and its worst-case alarm state — both comfortably clear the minimum operating voltage.

Scenario

Supply voltage24 V
Number of devices10
Standby draw per device0.5 mA
Alarm draw per device30 mA
Devices alarming simultaneously (worst case)1
End-of-line resistor10,000 Ω
Loop wiring resistance (round trip)20 Ω
Minimum operating voltage at farthest device16 V

Step-by-step calculation

Step 1: Compute standby-state current

Istandby = (numDevices x standbyMa) / 1000 + (Vsupply / Reol)
(10 x 0.5) / 1000 + (24 / 10,000)
Istandby = 0.0074 A (7.4 mA)

Step 2: Compute standby voltage at the farthest device

Vdevice = Vsupply - (Istandby x Rloop)
24 - (0.0074 x 20)
Vdevice(standby) = 23.85 V — passes the 16 V minimum easily

Step 3: Compute worst-case alarm-state current

One device switches to full alarm draw; the other nine remain at their standby draw.

Ialarm = (nAlarm x alarmMa + nStandby x standbyMa) / 1000 + EOLcurrent
(1 x 30 + 9 x 0.5) / 1000 + 0.0024
Ialarm = 0.0369 A (36.9 mA)

Step 4: Compute alarm-state voltage at the farthest device

Vdevice = Vsupply - (Ialarm x Rloop)
24 - (0.0369 x 20)
Vdevice(alarm) = 23.26 V — still passes the 16 V minimum with wide margin

Result summary

CheckRequirementActualStatus
Standby-state device voltage≥ 16 V23.85 V✓ PASS
Alarm-state device voltage≥ 16 V23.26 V✓ PASS
Both the quiescent standby condition (23.85 V) and the worst-case single-device alarm condition (23.26 V) leave this loop's farthest device well above its 16 V minimum operating voltage — this loop has substantial headroom for either more devices or a longer wiring run.

Key insight: Alarm-state voltage barely differs from standby-state voltage here (23.26 V vs 23.85 V) because only one device alarms at a time in this scenario — the moment more devices can alarm simultaneously (a real possibility in an actual fire event with multiple detectors triggering), alarm current climbs much faster and voltage at the farthest device drops correspondingly, which is exactly why 'worst-case simultaneous alarm count' is a deliberately conservative, adjustable input rather than always assuming just one device trips.

Try it with your own numbers

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Frequently asked questions

Why check both standby and alarm states instead of just the worst case?

Standby current is what the loop carries essentially all the time (supervising for wiring faults and device health), so it needs its own check for continuous reliable operation — while alarm current is a transient, higher-draw condition that has to be verified separately because it's the condition the whole system exists to detect and respond to correctly. A loop could pass one check and fail the other, so both need independent verification.

Why does the EOL resistor matter for standby current?

The end-of-line resistor provides continuous supervisory current specifically so the panel can distinguish a healthy loop from an open or short circuit — this small but constant EOL current adds to standby loop current and therefore standby voltage drop, which is why the calculator includes it in the standby calculation, though its relative contribution shrinks during alarm when device current dominates.

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