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Subtransient-reactance method8 min read

Worked Example: Fault Current Contribution from Two Paralleled Generators

Two identical 500 kVA gensets running in parallel — how much fault current does each one contribute to a common bus fault, and what does that mean for switchgear rating?

Scenario

System voltage415 V line-to-line
Genset 1500 kVA, Xd'' = 0.12 p.u.
Genset 2500 kVA, Xd'' = 0.12 p.u.
Example bus fault rating15 kA (for comparison)

Step-by-step calculation

Step 1: Compute each generator's rated current

Irated = (S x 1000) / (√3 x V x 1000)
Irated = 500,000 / (1.732 x 415)
Irated = 695.6 A per generator

Step 2: Compute each generator's subtransient fault contribution

The subtransient reactance Xd'' represents the generator's lowest impedance immediately after a fault occurs — the highest current it will momentarily deliver.

Ifault = Irated / Xd''
Ifault = 695.6 / 0.12
Ifault = 5797 A = 5.80 kA per generator

Step 3: Sum both generators' contributions at the common bus

This first-approximation method adds each machine's own-base contribution arithmetically, ignoring the (usually small) impedance of the bus and cabling between the two machines.

Itotal = Ifault(1) + Ifault(2)
Itotal = 5.80 + 5.80
Itotal = 11.59 kA

Step 4: Check the total against the bus/switchgear fault rating

Rated interrupting capacity ≥ total fault contribution
15 kA ≥ 11.59 kA
Passes, with about 29% margin

Result summary

CheckRequirementActualStatus
Fault contribution per generatorn/a (informational)5.80 kA each✓ PASS
Total fault current at common busn/a (informational)11.59 kA✓ PASS
Switchgear interrupting rating≥ 11.59 kA15 kA rated (example)✓ PASS
Each generator contributes 5.80 kA to a bus fault; combined, the two units deliver 11.59 kA, which the example 15 kA-rated switchgear clears with about 29% margin.

Key insight: Fault contribution scales with the number of paralleled machines, not just total installed capacity in isolation — adding a third identical generator would push total fault current toward 17.4 kA, which is exactly the kind of check that needs revisiting every time generation capacity is added to a paralleled bus, since existing switchgear may not have been rated for the new total.

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Frequently asked questions

Why use subtransient reactance instead of the generator's steady-state (synchronous) reactance?

Immediately after a fault, a generator's effective internal impedance is at its lowest (the subtransient value, Xd''), producing the highest instantaneous fault current — this is the value protective devices and switchgear must be rated to interrupt, even though the current decays toward a lower steady-state value over subsequent cycles as the transient and subtransient effects decay.

Does ignoring inter-machine impedance matter?

It's a simplifying assumption that's usually conservative for switchgear rating purposes (real bus/cable impedance between machines would slightly reduce the combined fault current), but it does not account for network impedance beyond the immediate bus, so it isn't a substitute for a full short-circuit study when sizing protection for a larger, more complex paralleled system.

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